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Problem Solving - Organize Data - Lesson 2.1

Use Picture Graphs - Lesson 2.2

Make Picture Graphs - Lesson 2.3

Use Bar Graphs - Lesson 2.4

Make a Bar Graph - Lesson 2.5

Solve Problems Using Data - Lesson 2.6

Use and Make Line Plots - Lesson 2.7

Number Patterns - Lesson 1.1

Round to Nearest Ten or Hundred - Lesson 1.2

Estimate Sums - Lesson 1.3

Mental Math Strategies for Addition - Lesson 1.4

Use Properties to Add - Lesson 1.5

Use the Break Apart Strategy to Add - Lesson 1.6

Use Place Value to Add - Lesson 1.7

Estimate Differences - Lesson 1.8

Mental Math Strategies for Subtraction - Lesson 1.9

Use Place Value to Subtract - Lesson 1.10

Combine Place Values to Subtract - Lesson 1.11

Describe Plane Shapes - Lesson 12.1

Describe Angles in Plane Shapes - Lesson 12.2

Identify Polygons - Lesson 12.3 ​

Describe Sides of Polygons - Lesson 12.4

​ Classify Quadrilaterals - Lesson 12.5

​Draw Quadrilaterals - Lesson 12.6

Describe Triangles - Lesson 12.7

Chapter 12 Performance Task Review For Test

Problem Solving - Compare Fractions - Lesson 9.1

Compare Fractions with the Same Denominator - Lesson 9.2

Compare Fractions with the Same Numerator - Lesson 9.3

Compare Fractions - Lesson 9.4

Compare and Order Fractions - Lesson 9.5

Model Equivalent Fractions - Lesson 9.6

Equivalent Fractions - Lesson 9.7

Divide by 2 - Lesson 7.1

Divide by 10 - Lesson 7.2

Divide by 5 - Lesson 7.3

Divide by 3 - Lesson 7.4

Divide by 4 - Lesson 7.5

Divide by 5 - Lesson 7.6

Mid-Chapter 7 Checkpoint on Division Facts and Strategies

Divide by 7 - Lesson 7.7

Divide by 8 - Lesson 7.8

Divide by 9 - Lesson 7.9

Problem Solving - Two-Step Problems - Lesson 7.10

Order of Operations - Lesson 7.11

Problem Solving - Model Division - Lesson 6.1

Size of Equal Groups - Lesson 6.2

Number of Equal Groups - Lesson 6.3

Model (Division) with Bar Model - Lesson 6.4

Relate Subtraction and Division - Lesson 6.5

Mid-Chapter 6 Checkpoint

Model (division) with Arrays - Lesson 6.6

Relate Multiplication and Division - Lesson 6.7

Write Related Facts - Lesson 6.8

Division Rules for 1 and 0 - Lesson 6.9

Chapter 6 Review for Test - Understanding Division

Multiply with 2 and 4 - Lesson 4.1

Multiply with 5 and 10 - Lesson 4.2

Multiply with 3 and 6 - Lesson 4.3

Distributive Property - Lesson 4.4

Multiply with 7 - Lesson 4.5

Associative Property of Multiplication - Lesson 4.6

Patterns on the Multiplication Table - Lesson 4.7

Multiply with 8 - Lesson 4.8

Multiply with 9 - Lesson 4.9

Review For Test on Chapter 4

Describe Patterns - Lesson 5.1

Find Unknown Factors - Lesson 5.2

Problem Solving: Using the Distributive Property - Lesson 5.3

Multiplication Strategies with Multiples of 10 - Lesson 5.4

Multiply Multiples of 10 by 1-Digit Numbers - Lesson 5.5

Chapter 5 Review on Multiplication Facts

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Model Perimeter - Lesson 11.1

Find Perimeter - Lesson 11.2

Find Unknown Side Lengths - Lesson 11.3

Understanding Area - Lesson 11.4

Measure Area - Lesson 11.5

Use Area Models - Lesson 11.6

Problem Solving - Area of Rectangles - Lesson 11.7

Area of Combined Rectangles - Lesson 11.8

Same Perimeter - Different Area - Lesson 11.9

Same Area - Different Perimeter - Lesson 11.10

Chapter 11 Review for Test on Perimeter and Area

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Count Equal Groups - Lesson 3.1

Relate Addition and Multiplication - Lesson 3.2

Skip Count on a Number Line - Lesson 3.3

Problem Solving - Model Multiplication - Lesson 3.4

Model with Arrays - Lesson 3.5

Commutative Property of Multiplication - Lesson 3.6

Multiply with 1 and 0 - Lesson 3.7

Time to the Minute - Lesson 10.1

A.M. and P.M. - Lesson 10.2

Measure Time Intervals - Lesson 10.3

Use Time Intervals - Lesson 10.4

Problem Solving - Time Intervals - Lesson 10.5

Measure Length - Lesson 10.6

Estimate and Measure Liquid Volume - Lesson 10.7

Estimate and Measure Mass - Lesson 10.8

Equal Parts of a Whole - Lesson 8.1

Equal Shares - Lesson 8.2

Unit Fractions of a Whole - Lesson 8.3

Fractions of a Whole - Lesson 8.4

Fractions on a Number Line - Lesson 8.5

Relate Fractions and Whole Numbers - Lesson 8.6

Fractions of a Group - Lesson 8.7

Find Part of Group Using Unit Fractions - Lesson 8.8

Problem Solving: Find the Whole Using Unit Fractions - Lesson 8.9

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Texas Go Math Grade 6 Lesson 10.3 Answer Key Order of Operations

Refer to our Texas Go Math Grade 6 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 6 Lesson 10.3 Answer Key Order of Operations.

Question 1. In C, why does it makes sense to write the values as powers? What is the pattern for the number of e-mails in each wave for Amy? Answer: It is easier to write the values as powers to identify the pattern that can be observed in the given situation. Pattern for the diagram of Amy: 1st wave = 3 1 = 3 2nd wave = 3 2 = 9 The pattern is 3 1 and 3 2 .

Simplify each expression using the order of operations.

Question 2. (3 – 1) 4 + 3 _______________ Answer: Evaluate the expression. = 2 4 + 3 subtract the numbers inside the parenthesis and evaluate the exponent = 16 + 3 add the numbers = 19 The simplified expression is 19.

Go Math 6th Grade Lesson 10.3 Answer Key Question 3. 24 ÷ (3 × 2 2 ) _______________ Answer: Evaluate the expression. = 24 ÷ (3 × 4) evaluate the exponent inside the parenthesis and multiply = 24 ÷ 12 divide the numbers = 2 The simplified expression is 2.

Question 4. – 7 × (- 4) ÷ 14 – 2 2 Answer: Evaluate the expression. = – 7 × (- 4) ÷ 14 – 4 evaluate the exponent = 28 ÷ 14 – 4 multiply – 7 and – 4 then divide the answer by 14 = 2 – 4 subtract the numbers = – 2 The simplified expression is – 2.

Question 5. – 5(- 3 + 1) 3 – 3 Answer: Evaluate the expression. = – 5 (- 2) 3 – 3 subtract the numbers inside the parenthesis and evaluate the exponent = – 5(- 8) – 3 multiply – 5 and – 8 = 40 – 3 subtract the numbers = 37

Texas Go Math Grade 6 Lesson 10.3 Guided Practice Answer Key

Complete to simplify each expression.

Question 2. 4 + (10 – 7) 2 ÷ 3 = 4 + ( ____________ ) 2 ÷ 3 = 4 + ____________ ÷ 3 = 4 + ____________ = ____________ Answer: Evaluate the expression. = 4 + 3 2 ÷ 3 subtract the numbers inside the parenthesis and evaluate the exponent = 4 + 9 ÷ 3 divide 9 by 3 = 4 + 3 add the number = 7 The simplified expression is 7.

Go Math Lesson 10.3 6th Grade Answer Key Question 3. 36 ÷ 2 2 – 4 × 2 = 36 ÷ ____________ – 4 × 2 = ____________ – 4 × 2 = ____________ – 8 = ____________ Answer: Evaluate the expression. = 36 ÷ 4 – 4 × 2 evaluate the exponent = 9 – 4 × 2 divide 36 by 4 then multiply 4 by 2 = 9 – 8 subtract the numbers = 1 The simplified expression is 1.

Question 4. 2 + (- 24 ÷ 2 3 ) – 9 = – 2 + (- 24 ÷ _________ ) – 9 = 2 + ____________ – 9 =____________ – 9 = ____________ Answer: Evaluate the expression = 2 + (- 24 ÷ 8) – 9 evaluate the exponent and divide the numbers inside the parenthesis = 2 + (- 3) – 9 subtract the numbers = – 1 – 9 add the numbers = – 10 The simplified expression is – 10

Question 5. – 4 2 × (- 3 × 2 + 8) = – 4 2 × (_______ + 8) = – 4 2 × _________ = _________ × _________ = _________ Answer: Evaluate the expression = – 4 2 × (-6 + 8) multiply – 3 by 2 inside the parenthesis and subtract = – 4 2 × 2 evaluate the exponent = 16 × 2 multiply the numbers = 32 The simplified expression is 32.

Essential Question Check – In

Question 6. How do you use the order of operations to simplify expressions with exponents? Answer: The order of operations to simplify expressions with exponents starts with simplifying the bracket (if any), solving the numerical value of power first, followed by division, multiplication, addition, and then subtraction.

Go Math Grade 6 Lesson 10.3 Answer Key Question 7. 5 × 2 + 3 2 __________ Answer: Solution to this example is given below = 5 × 2 + 3 2

5 × 2 + 3 2 = 5 × 2 + 9 Evaluate 3 2 . = 10 + 9 Multiply. = 19 Add. = 19

Question 8. 15 – 7 × 2 + 2 3 _____________ Answer: Solution to this example is given below 15 – 7 × 2 + 2 3 15 – 7 × 2 + 2 3 = 15 – 7 × 2 + 8 Evaluate 2. = 15 – 14 – 8 Multiply. = 1 + 8 Subtract. = 9 Add. = 9

Question 9. (11 – 8) 2 – 2 × 6 _____________ Answer: Evaluate the expression. = 3 2 – 2 × 6 subtract the numbers inside the parenthesis and evaluate the exponent = 9 – 2 × 6 multiply – 2 by 6 = 9 – 12 subtract the numbers = – 3 The simplified expression is – 3.

Question 10. 6 + 3(13 – 2) – 5 2 _____________ Answer: Solution to this example is given below 6 + 3(13 – 2) – 5 2

6 + 3(13 – 2) – 5 2 = 6 + 3(13 – 2) – 25 Evaluate 5 2 . = 6 + 3 × 11 – 25 Perform operations inside parentheses. = 6 + 33 – 25 Multiply. = 6 + 8 Subtract. = 14 Add. = 14

Question 11. 12 + \(\frac{9^{2}}{3}\) _____________ Answer: Solution to this example is given below 12 + \(\frac{9^{2}}{3}\)

12 + \(\frac{9^{2}}{3}\) = 12 + \(\frac{81}{3}\) Evaluate 9 2 . = 12 + 27 Divide. = 39 Add. = 39

Lesson 10.3 Answer Key Go Math Grade 6 Question 12. \(\frac{8+6^{2}}{11}\) + 7 × 2 _____________ Answer: The solution to this example is given below \(\frac{8+6^{2}}{11}\) + 7 × 2

\(\frac{8+6^{2}}{11}\) + 7 × 2 = \(\frac{8+6^{2}}{11}\) + 7 × 2 Evaluate 6 2 . = \(\frac{44}{11}\) + 7 × 2 Add. = 4 + 7 × 2 Divide. = 4 + 14 Multiply. = 18 Add.

Question 13. Explain the Error Jay simplified the expression – 3 × (3 + 12 ÷ 3) 4. For his first step, he added 3 + 12 to get 15. What was Jay’s error? Find the correct answer. Answer: Evaluate the expression = – 3 × (3 + 4) – 4 divide 12 by 3 then add to 3 = – 3 × 7 – 4 multiply – 3 by 7 = – 21 – 4 add the numbers = – 25 Jay made an error on his first step. In the order of operations, inside a parenthesis, division must be done first than addition, Therefore, the simplified expression is – 25.

a. Write and simplify an expression to find the amount Pani pays if a $3 discount is applied to her total. Answer: Evaluate the total cost when only 1 $3 off coupon is applied. Therefore, Cost = 3(12) + 2(19) – 3 = $71.

b. Pani says she should get a $3 discount on the price of each shirt and a $3 discount on the price of each pair of jeans. Write and simplify an expression to find the amount she would pay if this is true. Answer: Evaluate the total cost when only 1 $3 off coupon is applied. on every piece of clothing. Therefore, Cost = 3(12 – 3) + 2(19 – 3) = $59.

c. Analyze Relationships Why are the amounts Pani pays in a and b different? Answer: In a, the coupon is applied only once, while in b the coupon is applied for each piece of clothing, so here 5 times. This is why the result of b is $12 less than that of a.

d. If you were the shop owner, how would you change the sign? Explain. Answer: It would be better to write that $3 off the total purchase.

a. Look for a Pattern Write an expression for the number of butterflies after 4 minutes. Use a power of 2 in your answer. Answer: In the 1st minute there are 3 butterfLies on the screen and they double every minute, so here the repeating number is 2, so the expression for butterflies on the screen after n minutes is given by 3 × 2 n .

b. Write an expression for the number of butterflies remaining after Ellen captured the 7 butterflies. Simplify the expression. Answer: Use the expression obtained to soLve for n = 4 and subtract 7 from it, therefore: 3 × 2 4 – 7 = 41. There were 41 butterflies on the screen after 4 minutes and after Ellen had caught 7.

Question 16. Show how to write, evaluate and simplify an expression to represent and solve this problem: Jeff and his friend each text four classmates about a concert. Each classmate then texts four students from another school about the concert. If no one receives the message more than once, how many students from the other school receive a text about the concert? Answer: Jeff and his friend, so 2 people are texting 4 people each, so 2 × 4 = 8 people are being notified about the concert. Then each 8 of them texts to 4 more, so the total number of people of the other school to get notified about the concert are 8 × 4 = 32.

H.O.T. Focus on Higher Order Thinking

a. Write an expression for the area of the entire figure that includes an exponent. Then find the area. Answer: Area of the blue rectangle is 24 square inches, area of the white rectangle is 2 × 6 = 12 square inches, and area of the square is 6 2 = 36 square inches. Therefore the total area of the figure is 24 + 12 + 36 = 72 square inches.

b. Find the dimensions of the entire figure. Answer: The side length of the square is 6 inches and then there is an additional 2 units below it so it can be said that the left and right side length of the given figure is 6 + 2 = 8 inches. The area is 72 square inches so this can be divided by the obtained side length to evaluate the width of the rectangle, therefore: \(\frac{72}{8}\) = 9 inches. The figure is a rectangle with a length of 8 inches and a width of 9 inches.

Lesson 10.3 Answer Key 6th Grade Go Math Question 18. Analyze Relationships Roberto’s teacher writes the following statement on the board: The cube of a number plus one more than the square of the number is equal to the opposite of the number. Show that the number is – 1. Answer: Evaluate the expression. (- 1) 3 + 1 + (- 1) 2 = 1 translating the problem – 1 + 1 + 1 = 1 evaluate the exponents – 1 + 2 = 1 subtract the numbers 1 = 1 The expression is (- 1) 3 + 1 + (- 1) 2 = 1.

Question 19. Persevere in Problem Solving Use parentheses to make this statement true: 8 × 4 – 2 × 3 + 8 ÷ 2 = 25 Answer: Solution to this example is given below 8 × 4 – (2 × 3 + 8) ÷ 2 (we use parentheses like this)

8 × 4 – (2 × 3 + 8) ÷ 2 = 8 × 4 – (6 + 8) ÷ 2 Perform operations inside parentheses. = 8 × 4 – 14 ÷ 2 Perform operations inside parentheses = 8 × 4 – 7 Divide. = 32 – 7 Multiply. = 25 Subtract. = 25

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Go Math! 4 Common Core, Grade: 4 Publisher: Houghton Mifflin Harcourt

Go math 4 common core, title : go math 4 common core, publisher : houghton mifflin harcourt, isbn : 054758783x, isbn-13 : 9780547587837, use the table below to find videos, mobile apps, worksheets and lessons that supplement go math 4 common core., textbook resources.

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